y^2+4y-4x+12=0

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Solution for y^2+4y-4x+12=0 equation:


Simplifying
y2 + 4y + -4x + 12 = 0

Reorder the terms:
12 + -4x + 4y + y2 = 0

Solving
12 + -4x + 4y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -4x + 4y + -12 + y2 = 0 + -12

Reorder the terms:
12 + -12 + -4x + 4y + y2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -4x + 4y + y2 = 0 + -12
-4x + 4y + y2 = 0 + -12

Combine like terms: 0 + -12 = -12
-4x + 4y + y2 = -12

Add '-4y' to each side of the equation.
-4x + 4y + -4y + y2 = -12 + -4y

Combine like terms: 4y + -4y = 0
-4x + 0 + y2 = -12 + -4y
-4x + y2 = -12 + -4y

Add '-1y2' to each side of the equation.
-4x + y2 + -1y2 = -12 + -4y + -1y2

Combine like terms: y2 + -1y2 = 0
-4x + 0 = -12 + -4y + -1y2
-4x = -12 + -4y + -1y2

Divide each side by '-4'.
x = 3 + y + 0.25y2

Simplifying
x = 3 + y + 0.25y2

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